25n^2-285n+810=0

Solution for 25n^2-285n+810=0 equation:

25n^2-285n+810=0

a = 25; b = -285; c = +810;
Δ = b2-4ac
Δ = -2852-4·25·810
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-285)-15}{2*25}=\frac{270}{50}
=5+2/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-285)+15}{2*25}=\frac{300}{50}
=6
$